In Exercise?, ?use the following listed chest deceleration measurements (in g, where g? ?is the force of gravity) from samples of small, midsize, and large cars. (These values are from Data Set 13 in Appendix B.) Also shown (on the next page) are the SPSS results for analysis of variance. Assume that we plan to use a 0.05 significance level to test the claim that the different size categories have the same mean chest deceleration in the standard crash test. Chest Deceleration Measurements ?(g)? from a Standard Crash Test S m a l l M i d s i z e L a r g e P-?Value? If we use a 0.05 significance level in analysis of variance with the sample data given in Exercise, what is the ?P-?value? What should we conclude? ANOVA a.? What characteristic of the data above indicates that we should use ?one-way analysis of variance? b.? If the objective is to test the claim that the three size categories have the same mean? chest deceleration, why is the method referred to as analysis of ?variance?7.
Solution 4BSC Step 1 Question 4 We have been provided with chest declaration measurements from three samples of small, medium and large cars. Chest Declaration Measurements Small 44 39 37 54 39 44 42 Mediu 36 53 43 42 52 49 41 m Large 32 45 41 38 37 38 33 From the SPSS output is given below : Mea Sum of n df F Sig. squares Squ are 100. Betwee 200.857 2 429 3.28 n 549.714 18 .061 30.5 8 Groups 750.571 20 40 Within Groups Total