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An electron with kinetic energy Ke travels in a circular path that is perpendicular to a

Fundamentals of Physics, Volume 2 (Chapters 21 - 44) | 10th Edition | ISBN: 9781118230732 | Authors: David Halliday, Robert Resnick, Jearl Walker ISBN: 9781118230732 337

Solution for problem 43 Chapter 32

Fundamentals of Physics, Volume 2 (Chapters 21 - 44) | 10th Edition

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Fundamentals of Physics, Volume 2 (Chapters 21 - 44) | 10th Edition | ISBN: 9781118230732 | Authors: David Halliday, Robert Resnick, Jearl Walker

Fundamentals of Physics, Volume 2 (Chapters 21 - 44) | 10th Edition

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Problem 43

An electron with kinetic energy Ke travels in a circular path that is perpendicular to a uniform magnetic field, which is in the positive direction of a z axis. The electrons motion is subject only to the force due to the field. (a) Show that the magnetic dipole moment of the electron due to its orbital motion has magnitude m Ke/B and that it is in the direction opposite that of . What are the (b) magnitude and (c) direction of the magnetic dipole moment of a positive ion with kinetic energy Ki under the same circumstances? (d) An ionized gas consists of 5.3 1021 electrons/m3 and the same number density of ions. Take the average electron kinetic energy to be 6.2 1020 J and the average ion kinetic energy to be 7.6 1021 J. Calculate the magnetization of the gas when it is in a magnetic field of 1.2 T.

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Physics 151 Equations to Know Motion One Dimensional Two Dimensional = + ∆ = +( ) = + ∆ + .5 (∆ ) 2...

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Chapter 32, Problem 43 is Solved
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Textbook: Fundamentals of Physics, Volume 2 (Chapters 21 - 44)
Edition: 10
Author: David Halliday, Robert Resnick, Jearl Walker
ISBN: 9781118230732

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