One definition of the gamma function G(a) is given by the improper integral G(a) # q 0 t
Chapter 4, Problem 41(choose chapter or problem)
One definition of the gamma function \(\Gamma(\alpha)\) is given by the improper integral
\(\Gamma(\alpha)=\int_{0}^{\infty} t^{\alpha-1} e^{-t} d t\), \(\alpha>0\)
Use this definition to show that \(\Gamma(\alpha+1)=\alpha \Gamma(\alpha)\).
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