Answer: In 4346, use a CAS to solve the given system

Chapter 8, Problem 46

(choose chapter or problem)

If a vector \(\mathbf{a}=\overrightarrow{O P}=\langle x, y\rangle \text { in } R^{2}\) is rotated counterclockwise about the origin through an angle \(\theta\), then the components of the resulting vector \(\mathbf{b}=\overrightarrow{O P_{1}}=\left\langle x_{1}, y_{1}\right\rangle\) are given by B = MA. where

\(\mathbf{A}=\left(\begin{array}{l} x \\ y \end{array}\right), \mathbf{B}=\left(\begin{array}{l} x_{1} \\ y_{1} \end{array}\right) \text {, and } \mathbf{M}=\left(\begin{array}{cc} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{array}\right)\).

The \(2\ \times\ 2\) matrix M is called a rotation matrix. See Figure 8.1.1. In Problems 45-48, find the resulting vector b if the given vector \(\mathbf{a}=\overrightarrow{O P}=\langle x, y\rangle\) is rotated through the indicated angle.

\(\mathbf{a}=\langle-2,4\rangle, \theta=\pi / 6\)

Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.

Becoming a subscriber
Or look for another answer

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back