Solution: In 712, expand f (z) 1 z(z 2 3) in a Laurent series valid for the indicated
Chapter 19, Problem 10(choose chapter or problem)
In Problems 7–12, expand \(f(z)=\frac{1}{z(z-3)}\) in a Laurent series valid for the indicated annular domain.
\(|z-3|>3\)
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