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A d-ary tree is a rooted tree in which each node has at most d children. Show that any
Chapter 1, Problem 1.3(choose chapter or problem)
A d-ary tree is a rooted tree in which each node has at most d children. Show that any d-ary tree with n nodes must have a depth of \(\Omega(\log n / \log d)\). Can you give a precise formula for the minimum depth it could possibly have?
Questions & Answers
QUESTION:
A d-ary tree is a rooted tree in which each node has at most d children. Show that any d-ary tree with n nodes must have a depth of \(\Omega(\log n / \log d)\). Can you give a precise formula for the minimum depth it could possibly have?
ANSWER:Step 1 of 3
A d-ary tree with n nodes must have a depth of
A d-ary tree of height h has at most vertices. We can prove this inductively.
(a) Claim: A d-ary tree of height h has at most vertices
(b) Base Case: When the height of h of the tree is 1, the number of vertices is at most . Therefore, the statement is true when
(c) Induction hypothesis: The statement is true when the height h of the tree is
(d) Induction step: We will show that the statement is still true when . A d – ary tree of height consists of a root that has at most d children, each of which is the root of a subtree with height at most k. By the Induction hypothesis, the number of vertices in a d-ary tree of height is at most . Therefore, a tree with height has at most vertices. Hence, a tree with height K + 1 has at most vertices. We have completed the induction.