Large objects have inertia and tend to keep

Chapter 6, Problem 65P

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QUESTION:

Large objects have inertia and tend to keep movingNewton's first law. Life is very different for small microorganisms that swim through water. For them, drag forces are so large that they instantly stop, without coasting, if they cease their swimming motion. To swim at constant speed, they must exert a constant propulsion force by rotating corkscrew-like flagella or beating hair-like cilia. The quadratic model of drag of Equation 6.16 fails for very small particles. Instead, a small object moving in a liquid experiences a linear drag force, \(\vec{D}=(b v\), direction opposite the motion), where \(b\) is a constant. For a sphere of radius \(R\), the drag constant can be shown to be \(b=6 \pi \eta R\), where \(\eta\) is the viscosity of the liquid. Water at \(20^{\circ} \mathrm{C}\) has viscosity \(1.0 \times 10^{-3} \mathrm{~N} \mathrm{~s} / \mathrm{m}^{2}\).

a. A paramecium is about \(100 \mu \mathrm{m}\) long. If it's modeled as a sphere, how much propulsion force must it exert to swim at a typical speed of \(1.0 \mathrm{~mm} / \mathrm{s}\)? How about the propulsion force of a \(2.0-\mu \mathrm{m}\)-diameter \(E\). coli bacterium swimming at \(30 \mu \mathrm{m} / \mathrm{s}\) ?

b. The propulsion forces are very small, but so are the organisms. To judge whether the propulsion force is large or small relative to the organism, compute the acceleration that the propulsion force could give each organism if there were no drag. The density of both organisms is the same as that of water, \(1000 \mathrm{~kg} / \mathrm{m}^{3}\).

Equation Transcription:

Text Transcription:

vec{D}=(b v

b

R

b = 6 pi eta R

eta

20^circ C

1.0 X 10^{-3} Ns/m^2

100 mu m

1.0 mm/ s

2.0-mu m

E

30 mu m/s

1000 kg / m^3

Questions & Answers

QUESTION:

Large objects have inertia and tend to keep movingNewton's first law. Life is very different for small microorganisms that swim through water. For them, drag forces are so large that they instantly stop, without coasting, if they cease their swimming motion. To swim at constant speed, they must exert a constant propulsion force by rotating corkscrew-like flagella or beating hair-like cilia. The quadratic model of drag of Equation 6.16 fails for very small particles. Instead, a small object moving in a liquid experiences a linear drag force, \(\vec{D}=(b v\), direction opposite the motion), where \(b\) is a constant. For a sphere of radius \(R\), the drag constant can be shown to be \(b=6 \pi \eta R\), where \(\eta\) is the viscosity of the liquid. Water at \(20^{\circ} \mathrm{C}\) has viscosity \(1.0 \times 10^{-3} \mathrm{~N} \mathrm{~s} / \mathrm{m}^{2}\).

a. A paramecium is about \(100 \mu \mathrm{m}\) long. If it's modeled as a sphere, how much propulsion force must it exert to swim at a typical speed of \(1.0 \mathrm{~mm} / \mathrm{s}\)? How about the propulsion force of a \(2.0-\mu \mathrm{m}\)-diameter \(E\). coli bacterium swimming at \(30 \mu \mathrm{m} / \mathrm{s}\) ?

b. The propulsion forces are very small, but so are the organisms. To judge whether the propulsion force is large or small relative to the organism, compute the acceleration that the propulsion force could give each organism if there were no drag. The density of both organisms is the same as that of water, \(1000 \mathrm{~kg} / \mathrm{m}^{3}\).

Equation Transcription:

Text Transcription:

vec{D}=(b v

b

R

b = 6 pi eta R

eta

20^circ C

1.0 X 10^{-3} Ns/m^2

100 mu m

1.0 mm/ s

2.0-mu m

E

30 mu m/s

1000 kg / m^3

ANSWER:

Step 1 of 5

We have to find the propulsion force exerted by a paramecium and E. coli bacterium to swim at a typical speed of \(1.0 \mathrm{~mm} / \mathrm{s}\) and \(30 \mu \mathrm{m} / \mathrm{s}\).

The propulsion force exerted by paramecium and \(E\). coli bacterium is equal to the drag force.

                                               \(F_{p r o p}=F_{D r a g}\)

The paramecium and \(\mathrm{E}\). Coli bacterium is modeled as a sphere so they experience a linear drag force given by the expression.

                                               \(F_{\text {Drag }}=6 \pi \eta R v\)

Where,

                                               \(\eta =\text { viscosity of water }\)

                                               \(=1.0 \times 10^{-3} \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}\)

                                               \(R =\text { Radius in } \mathrm{m}\)

                                               \(v =\text { speed in } \mathrm{m} / \mathrm{s}\)

 

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