In a ballistics test, a 25 g bullet traveling horizontally at 1200 m/s goes through a 30-cm-thick 350 kg stationary target and emerges with a speed of 900 m/s. The target is free to slide on a smooth horizontal surface. What is the target’s speed just after the bullet emerges?
Step 1 of 3:
We are going to find the speed of the target as it is penetrated by a fast moving bullet.
The mass of the bullet m1 = 25 g = 0.025 kg
The initial speed of the bullet v1b = 1200 m/s
The final speed of the bullet v2b = 900 m/s
The mass of the target m2 = 350 kg
The initial speed of the target v1t = 0
The thickness of the target Δx = 30 cm = 0.30 m