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A 1500 kg weather rocket accelerates upward at . It
Chapter 9, Problem 47P(choose chapter or problem)
A 1500 kg weather rocket accelerates upward at \(10 \mathrm{~m} / \mathrm{s}^{2}\). It explodes 2.0 s after liftoff and breaks into two fragments, one twice as massive as the other. Photos reveal that the lighter fragment traveled straight up and reached a maximum height of 530 m. What were the speed and direction of the heavier fragment just after the explosion?
Equation Transcription:
Text Transcription:
10 m/s^2
Questions & Answers
QUESTION:
A 1500 kg weather rocket accelerates upward at \(10 \mathrm{~m} / \mathrm{s}^{2}\). It explodes 2.0 s after liftoff and breaks into two fragments, one twice as massive as the other. Photos reveal that the lighter fragment traveled straight up and reached a maximum height of 530 m. What were the speed and direction of the heavier fragment just after the explosion?
Equation Transcription:
Text Transcription:
10 m/s^2
ANSWER:
Step 1 of 5
We are going to find the speed and the direction of the heavier fragment from the exploded weather rocket. We need to find the speed of the lighter fragment after the explosion to find the speed of the heavier fragment using the conservation of momentum principle.
The mass of the rocket \(\mathrm{m}=1500 \mathrm{~kg}\)
The mass of the lighter object \(\mathrm{m}_{1}=500 \mathrm{~kg}\)
The mass of the heavier object \(\mathrm{m}_{2}=1000 \mathrm{~kg}\)
The acceleration of the rocket \(\mathrm{a}_{\mathrm{y}}=10 \mathrm{~m} / \mathrm{s}^{2}\)
The acceleration due to gravity \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\)
The time \(\mathrm{t}=2 \mathrm{~s}\) (when explodes)
The distance traveled by the lighter fragment after the rocket explodes \(\mathrm{y}_{2}=530 \mathrm{~m}\)