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When 2.25 mg of anthracene, C14H10(s), was burned in a bomb calorimeter the temperature
Chapter 2, Problem 2.19(b)(choose chapter or problem)
When 2.25 mg of anthracene, C14H10(s), was burned in a bomb calorimeter the temperature rose by 1.35 K. Calculate the calorimeter constant. By how much will the temperature rise when 135 mg of phenol, C6H5OH(s), is burned in the calorimeter under the same conditions? (cH7(C14H10, s) = 7061 kJ mol1.)
Questions & Answers
QUESTION:
When 2.25 mg of anthracene, C14H10(s), was burned in a bomb calorimeter the temperature rose by 1.35 K. Calculate the calorimeter constant. By how much will the temperature rise when 135 mg of phenol, C6H5OH(s), is burned in the calorimeter under the same conditions? (cH7(C14H10, s) = 7061 kJ mol1.)
ANSWER:Problem 2.19(b)
When 2.25 mg of anthracene, C14H10(s), was burned in a bomb calorimeter the temperature rose by 1.35 K. Calculate the calorimeter constant. By how much will the temperature rise when 135 mg of phenol, C6H5OH(s), is burned in the calorimeter under the same conditions?
Step by Step Solution
Step 1 of 5
Combustion reaction of anthracene is as follows.