Protons and neutrons (together called nucleons)are held

Chapter 10, Problem 60P

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QUESTION:

Protons and neutrons (together called nucleons) are held together in the nucleus of an atom by a force called the strong force. At very small separations, the strong force between two nucleons is larger than the repulsive electrical force between two protons - hence its name. But the strong force quickly weakens as the distance between the protons increases. A well-established model for the potential energy of two nucleons interacting via the strong force is

                                                   

                                                                                   \(U=U_{0}\left[1-e^{-x / x_{0}}\right]\)

where \(x\) is the distance between the centers of the two nucleons, \(x_{0}\) is a constant having the value \(x_{0}=2.0 \times 10^{-15} \mathrm{~m}\), and \(U_{0}=6.0 \times 10^{-11} \mathrm{~J}\)

a. Calculate and draw an accurate potential-energy curve from \(x=0 \mathrm{~m}\) to \(x=10 \times 10^{-15} \mathrm{~m}\). Either use your calculator to compute the value at several points or use computer software.

b. Quantum effects are essential for a proper understanding of how nucleons behave. Nonetheless, let us innocently consider two neutrons as if they were small, hard, electrically neutral spheres of mass \(1.67 \times 10^{-27} \mathrm{~kg}\) and diameter \(1.0 \times 10^{-15} \mathrm{~m}\). (We will consider neutrons rather than protons so as to avoid complications from the electric forces between protons.) You are going to hold two neutrons \(5.0 \times 10^{-15} \mathrm{~m}\) apart, measured between their centers, then release them. Draw the total energy line for this situation on your diagram of part a.

c. What is the speed of each neutron as they crash together? Keep in mind that both neutrons are moving.

Equation Transcription:

Text Transcription:

U = U_{0}[1-e^{-x / x_{0}}]

x

x_0

x_0 = 2.0 X 10^-15 m

U_0 = 6.0 X 10^11 J

x = 0 m

x = 10 X 10^-15 m

1.67 X 10^-27 kg

1.0 X 10^-15 m

5.0 X 10^-15 m

Questions & Answers

QUESTION:

Protons and neutrons (together called nucleons) are held together in the nucleus of an atom by a force called the strong force. At very small separations, the strong force between two nucleons is larger than the repulsive electrical force between two protons - hence its name. But the strong force quickly weakens as the distance between the protons increases. A well-established model for the potential energy of two nucleons interacting via the strong force is

                                                   

                                                                                   \(U=U_{0}\left[1-e^{-x / x_{0}}\right]\)

where \(x\) is the distance between the centers of the two nucleons, \(x_{0}\) is a constant having the value \(x_{0}=2.0 \times 10^{-15} \mathrm{~m}\), and \(U_{0}=6.0 \times 10^{-11} \mathrm{~J}\)

a. Calculate and draw an accurate potential-energy curve from \(x=0 \mathrm{~m}\) to \(x=10 \times 10^{-15} \mathrm{~m}\). Either use your calculator to compute the value at several points or use computer software.

b. Quantum effects are essential for a proper understanding of how nucleons behave. Nonetheless, let us innocently consider two neutrons as if they were small, hard, electrically neutral spheres of mass \(1.67 \times 10^{-27} \mathrm{~kg}\) and diameter \(1.0 \times 10^{-15} \mathrm{~m}\). (We will consider neutrons rather than protons so as to avoid complications from the electric forces between protons.) You are going to hold two neutrons \(5.0 \times 10^{-15} \mathrm{~m}\) apart, measured between their centers, then release them. Draw the total energy line for this situation on your diagram of part a.

c. What is the speed of each neutron as they crash together? Keep in mind that both neutrons are moving.

Equation Transcription:

Text Transcription:

U = U_{0}[1-e^{-x / x_{0}}]

x

x_0

x_0 = 2.0 X 10^-15 m

U_0 = 6.0 X 10^11 J

x = 0 m

x = 10 X 10^-15 m

1.67 X 10^-27 kg

1.0 X 10^-15 m

5.0 X 10^-15 m

ANSWER:

Step 1 of 4

Part (a)

Our aim is to calculate the potential energy of the two nueleons and plot the curve.

The potential energy of the two nucleons is expressed as

\(U=U_{o}\left[1-e^{\left(-x / x_{o}\right)}\right]\)

Where \(\mathrm{U}_{\mathrm{o}}\) and \(\mathrm{x}_{\mathrm{o}}\) are the constants. And \(\mathrm{x}\) is the distance between the centers of the two nucleons.

\(\mathrm{U}_{\mathrm{o}}=6 \times 10^{-11} \mathrm{~J}\)

\(\mathrm{x}_{0}=2 \times 10^{-15} \mathrm{~m}\)

We are going to plot the potential energy curve between the points \(\mathrm{x}=0\) and \(10 \times 10^{-15} \mathrm{~m}\)

 

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