Solution Found!
Section 12.10 The Vector Description of
Chapter 12, Problem 43E(choose chapter or problem)
What are the magnitude and direction of the angular momentum relative to the origin of the \(100g\) particle in Figure EX12.43?
Equation Transcription:
Text Transcription:
100 g
Questions & Answers
QUESTION:
What are the magnitude and direction of the angular momentum relative to the origin of the \(100g\) particle in Figure EX12.43?
Equation Transcription:
Text Transcription:
100 g
ANSWER:Step 1 of 3
Our aim is to find the magnitude and the direction of the particle with respect to the origin.
The mass of the particle \(\mathrm{m}=100 \mathrm{~g}=0.1 \mathrm{~kg}\)
The position of the particle with respect to the origin is given by \(\vec{r}=(3 \hat{i}+2 \hat{j}) \mathrm{m}\)
The particle moves in the \(+y\) direction, and it is given as \(\vec{v}=(4 \hat{j}) \mathrm{m} / \mathrm{s}\)
The angular momentum (L) is given by
\(\vec{L}=\vec{r} \times m \vec{v}\)