Solution Found!
Section 13.3 Newton’s Law of GravityA 1.0-m-diameter lead
Chapter 13, Problem 4E(choose chapter or problem)
Problem 4E
Section 13.3 Newton’s Law of Gravity
A 1.0-m-diameter lead sphere has a mass of 5900 kg. A dust particle rests on the surface. What is the ratio of the gravitational force of the sphere on the dust particle to the gravitational force of the earth on the dust particle?
Questions & Answers
QUESTION:
Problem 4E
Section 13.3 Newton’s Law of Gravity
A 1.0-m-diameter lead sphere has a mass of 5900 kg. A dust particle rests on the surface. What is the ratio of the gravitational force of the sphere on the dust particle to the gravitational force of the earth on the dust particle?
ANSWER:
Step 1 of 1
Our aim is to find the ratio of gravitational forces on the dust particle on the sphere due to the sphere and the Earth.
The mass of the sphere \(\mathrm{m}_{\mathrm{s}}=5900 \mathrm{~kg}\)
The radius of the sphere \(\mathrm{r}=0.5 \mathrm{~m} \quad\) (diameter \(\mathrm{d}=1.0 \mathrm{~m}\) )
The mass of the dust \(=\mathrm{m}\)
The mass of the Earth \(\mathrm{M}=5.98 \times 10^{24} \mathrm{~kg}\)
The radius of the Earth \(\mathrm{R}=6.37 \times 10^{6} \mathrm{~m}\)