Solved: The free-fall acceleration at the surface of

Chapter 13, Problem 6CQ

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QUESTION:

The free-fall acceleration at the surface of planet 1 is \(20 \mathrm{~m} / \mathrm{s}^{2}\). The radius and the mass of planet 2 are twice those of planet 1 . What is \(g\) on planet 2 ?

Equation Transcription:

Text Transcription:

20 m/s^2

Questions & Answers

QUESTION:

The free-fall acceleration at the surface of planet 1 is \(20 \mathrm{~m} / \mathrm{s}^{2}\). The radius and the mass of planet 2 are twice those of planet 1 . What is \(g\) on planet 2 ?

Equation Transcription:

Text Transcription:

20 m/s^2

ANSWER:

Step 1 of 2

The objective here is to calculate the acceleration of freefall in a planet if the acceleration of freefall in another planet is known and the relation between the masses and radii of both the planets is given.

 

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