In are given the equation(s) used to solve a

Chapter 13, Problem 59P

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QUESTION:

In Problems 59 through 61 you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation(s).

b. Draw a pictorial representation.

c. Finish the solution of the problem.

\(\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.68 \times 10^{26} \mathrm{~kg}\right)}{r^{2}}\)

            \(=\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)}{\left(6.37 \times 10^{6} \mathrm{~m}\right)^{2}}\)

Equation Transcription:

Text Transcription:

(6.67 times 10^−11 Nm^2/kg^2)(5.68 times 10^26 kg)/r^2

=(6.67 times 10^−11 N m^2/kg^2)(5.98 times 10^24 kg)/(6.37 times 10^6 m)^2

Questions & Answers

QUESTION:

In Problems 59 through 61 you are given the equation(s) used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation(s).

b. Draw a pictorial representation.

c. Finish the solution of the problem.

\(\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.68 \times 10^{26} \mathrm{~kg}\right)}{r^{2}}\)

            \(=\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)}{\left(6.37 \times 10^{6} \mathrm{~m}\right)^{2}}\)

Equation Transcription:

Text Transcription:

(6.67 times 10^−11 Nm^2/kg^2)(5.68 times 10^26 kg)/r^2

=(6.67 times 10^−11 N m^2/kg^2)(5.98 times 10^24 kg)/(6.37 times 10^6 m)^2

ANSWER:

Step 1 of 2

a)

The equation is,

\(\frac{6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2} \times 5.68 \times 10^{26} \mathrm{~kg}}{r^{2}}=\frac{6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2} \times 5.98 \times 10^{24} \mathrm{~kg}}{\left(6.67 \times 10^{5}\right)^{3}}\)

We know that, the mass of satum is \(5.68 \times 10^{26} \mathrm{~kg}\).

The mass of earth is \(5.98 \times 10^{24} \mathrm{~kg}\).

So, the problem is basically to find the distance from the center of satum, where the acceleration due to gravity will be same as we experience on earth's surface.

 

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