Solution Found!
In are given the equation(s) used to solve a
Chapter 13, Problem 59P(choose chapter or problem)
In Problems 59 through 61 you are given the equation(s) used to solve a problem. For each of these, you are to
a. Write a realistic problem for which this is the correct equation(s).
b. Draw a pictorial representation.
c. Finish the solution of the problem.
\(\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.68 \times 10^{26} \mathrm{~kg}\right)}{r^{2}}\)
\(=\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)}{\left(6.37 \times 10^{6} \mathrm{~m}\right)^{2}}\)
Equation Transcription:
Text Transcription:
(6.67 times 10^−11 Nm^2/kg^2)(5.68 times 10^26 kg)/r^2
=(6.67 times 10^−11 N m^2/kg^2)(5.98 times 10^24 kg)/(6.37 times 10^6 m)^2
Questions & Answers
QUESTION:
In Problems 59 through 61 you are given the equation(s) used to solve a problem. For each of these, you are to
a. Write a realistic problem for which this is the correct equation(s).
b. Draw a pictorial representation.
c. Finish the solution of the problem.
\(\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.68 \times 10^{26} \mathrm{~kg}\right)}{r^{2}}\)
\(=\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)}{\left(6.37 \times 10^{6} \mathrm{~m}\right)^{2}}\)
Equation Transcription:
Text Transcription:
(6.67 times 10^−11 Nm^2/kg^2)(5.68 times 10^26 kg)/r^2
=(6.67 times 10^−11 N m^2/kg^2)(5.98 times 10^24 kg)/(6.37 times 10^6 m)^2
ANSWER:
Step 1 of 2
a)
The equation is,
\(\frac{6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2} \times 5.68 \times 10^{26} \mathrm{~kg}}{r^{2}}=\frac{6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2} \times 5.98 \times 10^{24} \mathrm{~kg}}{\left(6.67 \times 10^{5}\right)^{3}}\)
We know that, the mass of satum is \(5.68 \times 10^{26} \mathrm{~kg}\).
The mass of earth is \(5.98 \times 10^{24} \mathrm{~kg}\).
So, the problem is basically to find the distance from the center of satum, where the acceleration due to gravity will be same as we experience on earth's surface.