Solution Found!
In are given the equation(s) used to solve a
Chapter 13, Problem 60P(choose chapter or problem)
In Problems 59 through 61 you are given the equation(s) used to solve a problem. For each of these, you are to
a. Write a realistic problem for which this is the correct equation(s).
b. Draw a pictorial representation.
c. Finish the solution of the problem.
\(\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)(1000 \mathrm{~kg})}{r^{2}}\)
\(=\frac{(1000 \mathrm{~kg})(1997 \mathrm{~m} / \mathrm{s})^{2}}{r}\)
Equation Transcription:
Text Transcription:
(6.67 times 10^−11 Nm^2/kg^2)(5.98 times 10^24 kg)(1000 kg)/r^2
=(1000 kg)(1997 m/s)^2/r
Questions & Answers
QUESTION:
In Problems 59 through 61 you are given the equation(s) used to solve a problem. For each of these, you are to
a. Write a realistic problem for which this is the correct equation(s).
b. Draw a pictorial representation.
c. Finish the solution of the problem.
\(\frac{\left(6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2}\right)\left(5.98 \times 10^{24} \mathrm{~kg}\right)(1000 \mathrm{~kg})}{r^{2}}\)
\(=\frac{(1000 \mathrm{~kg})(1997 \mathrm{~m} / \mathrm{s})^{2}}{r}\)
Equation Transcription:
Text Transcription:
(6.67 times 10^−11 Nm^2/kg^2)(5.98 times 10^24 kg)(1000 kg)/r^2
=(1000 kg)(1997 m/s)^2/r
ANSWER:
Step 1 of 3
a)
Here we have to write a realistic problem for the f=given equation.
The equation is,
This equation resembles to a 1000 kg satellite orbiting the earth at a distance of “r”.
Because the mass of the earth is kg.
The left hand side is a force and the right side is mass times the velocity squared divided by the distance.
We know that, is the centripetal force.
This is why, it seems like a rocket of mass 1000 kg is moving around earth at a distance of “r” and the speed is 1997 m/s..