Section 15.6 Elasticitya. What is the pressure at a depth

Step 1 of 3

a) We need to find out the pressure at a depth of \(5000 \mathrm{~m}\) in the ocean.

The pressure at a depth of \(5000 \mathrm{~m}\) in the ocean is given by,

\(p=p_{a t m}+\rho_{w} g h\)

Atmospheric pressure, \(p_{a t m}=1.013 \times 10^{5} \mathrm{~Pa}\)

Density of water, \(\rho_{w}=1030 \mathrm{~kg} / \mathrm{m}^{3}\)

The depth distance, \(h=5000 \mathrm{~m}\)

So,

\(p=1.013 \times 10^{5} \mathrm{~Pa}+\left(1030 \mathrm{~kg} / \mathrm{m}^{3}\right)\left(9.8 \mathrm{~m} / \mathrm{s}^{2}\right)(5000 \mathrm{~m})\)

\(p=5.057 \times 10^{7} \mathrm{~Pa}\)

The pressure at a depth of \(5000 \mathrm{~m}\) in the ocean is \(p=5.057 \times 10^{7} \mathrm{~Pa}\).