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The arsenic in a 1.22-g sample of a pesticide was

Chapter 4, Problem 113IE

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QUESTION:

Problem 113IE

The arsenic in a 1.22-g sample of a pesticide was converted to AsO43- by suitable chemical treatment. It was then titrated using Ag+ to form Ag3AsO4 as a precipitate.

(a) What is the oxidation state of As in AsO43-?

(b) Name Ag3AsO4 by analogy to the corresponding compound containing phosphorus in place of arsenic.

(c) If it took 25.0 mL of 0.102 M Ag+ to reach the equivalence point in this titration, what is the mass percentage of arsenic in the pesticide?

Questions & Answers

QUESTION:

Problem 113IE

The arsenic in a 1.22-g sample of a pesticide was converted to AsO43- by suitable chemical treatment. It was then titrated using Ag+ to form Ag3AsO4 as a precipitate.

(a) What is the oxidation state of As in AsO43-?

(b) Name Ag3AsO4 by analogy to the corresponding compound containing phosphorus in place of arsenic.

(c) If it took 25.0 mL of 0.102 M Ag+ to reach the equivalence point in this titration, what is the mass percentage of arsenic in the pesticide?

ANSWER:

Problem 113IE

The arsenic in a 1.22-g sample of a pesticide was converted to AsO43- by suitable chemical treatment. It was then titrated using Ag+ to form Ag3AsO4 as a precipitate.

(a) What is the oxidation state of As in AsO43-?

(b) Name Ag3AsO4 by analogy to the corresponding compound containing phosphorus in place of arsenic.

(c) If it took 25.0 mL of 0.102 M Ag+ to reach the equivalence point in this titration, what is the mass percentage of arsenic in the pesticide?

                                                               Step by Step Solution

Step 1 of 3

a)

Let’s calculate the oxidation state of “As” ins .

The oxidation state of oxygen = -2


                 

                 

Therefore, the oxidation state of “As” is +5 in  ion.

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