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The arsenic in a 1.22-g sample of a pesticide was
Chapter 4, Problem 113IE(choose chapter or problem)
Problem 113IE
The arsenic in a 1.22-g sample of a pesticide was converted to AsO43- by suitable chemical treatment. It was then titrated using Ag+ to form Ag3AsO4 as a precipitate.
(a) What is the oxidation state of As in AsO43-?
(b) Name Ag3AsO4 by analogy to the corresponding compound containing phosphorus in place of arsenic.
(c) If it took 25.0 mL of 0.102 M Ag+ to reach the equivalence point in this titration, what is the mass percentage of arsenic in the pesticide?
Questions & Answers
QUESTION:
Problem 113IE
The arsenic in a 1.22-g sample of a pesticide was converted to AsO43- by suitable chemical treatment. It was then titrated using Ag+ to form Ag3AsO4 as a precipitate.
(a) What is the oxidation state of As in AsO43-?
(b) Name Ag3AsO4 by analogy to the corresponding compound containing phosphorus in place of arsenic.
(c) If it took 25.0 mL of 0.102 M Ag+ to reach the equivalence point in this titration, what is the mass percentage of arsenic in the pesticide?
ANSWER:
Problem 113IE
The arsenic in a 1.22-g sample of a pesticide was converted to AsO43- by suitable chemical treatment. It was then titrated using Ag+ to form Ag3AsO4 as a precipitate.
(a) What is the oxidation state of As in AsO43-?
(b) Name Ag3AsO4 by analogy to the corresponding compound containing phosphorus in place of arsenic.
(c) If it took 25.0 mL of 0.102 M Ag+ to reach the equivalence point in this titration, what is the mass percentage of arsenic in the pesticide?
Step by Step Solution
Step 1 of 3
a)
Let’s calculate the oxidation state of “As” ins .
The oxidation state of oxygen = -2
Therefore, the oxidation state of “As” is +5 in ion.
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