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Get Full Access to Chemistry: The Central Science - 12 Edition - Chapter 4 - Problem 81e
Get Full Access to Chemistry: The Central Science - 12 Edition - Chapter 4 - Problem 81e

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# Solution: Solution Stoichiometry and Chemical Analysis

ISBN: 9780321696724 27

## Solution for problem 81E Chapter 4

Chemistry: The Central Science | 12th Edition

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Problem 81E

Problem 81E

Solution Stoichiometry and Chemical Analysis (Section)

(a) What volume of 0.115 M HClO4 solution is needed to neutralize 50.00 mL of 0.0875 MNaOH?

(b) What volume of 0.128 M HCl is needed to neutralize 2.87 g of Mg(OH)2?

(c) If 25.8 mL of an AgNO3 solution is needed to precipitate all the Cl- ions in a 785-mg sample of KCl (forming AgCl), what is the molarity of the AgNO3 solution?

(d) If 45.3 mL of a 0.108 M HCl solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution?

Step-by-Step Solution:
Step 1 of 3

CHEM 112 Notes (1-13-16) Clicker Question: Calculate the molarity of a 12.0% sulfuric acid solution (2 SO4; 98.08 g/mol) having a density of 1.080 g/mL. = 12% H S2 4 MM=98.08 g/mol d=1.080 g/mol 12g H 2O (4er 100g of solution) 12 24 98.08 /= 0.122 24 100 ×1 1.080 = 92.59 = 0.09259 0.122 24= 1.32

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Step 3 of 3

##### ISBN: 9780321696724

This full solution covers the following key subjects: solution, needed, neutralize, Volume, agno. This expansive textbook survival guide covers 49 chapters, and 5471 solutions. Since the solution to 81E from 4 chapter was answered, more than 397 students have viewed the full step-by-step answer. The answer to “Solution Stoichiometry and Chemical Analysis (Section)(a) What volume of 0.115 M HClO4 solution is needed to neutralize 50.00 mL of 0.0875 MNaOH? (b) What volume of 0.128 M HCl is needed to neutralize 2.87 g of Mg(OH)2? (c) If 25.8 mL of an AgNO3 solution is needed to precipitate all the Cl- ions in a 785-mg sample of KCl (forming AgCl), what is the molarity of the AgNO3 solution? (d) If 45.3 mL of a 0.108 M HCl solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution?” is broken down into a number of easy to follow steps, and 98 words. The full step-by-step solution to problem: 81E from chapter: 4 was answered by , our top Chemistry solution expert on 04/03/17, 07:58AM. Chemistry: The Central Science was written by and is associated to the ISBN: 9780321696724. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 12.

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