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Earth’s oceans have an average depth of 3800 m, a total area of 3.63x10^8 km^2 , and an average concentration of dissolved gold of 5.8x10^-9 g/L. How many grams of gold are in the oceans?

Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg ISBN: 9780073511085 71

Solution for problem 71P Chapter 1

Principles of General Chemistry | 2nd Edition

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Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg

Principles of General Chemistry | 2nd Edition

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Problem 71P

Earth’s oceans have an average depth of 3800 m, a total area of \(3.63\times10^8\ \text{km}^2\), and an average concentration of dissolved gold of \(5.8\times10^{-9}\ \text{g/L}\). (a) How many grams of gold are in the oceans? (b) How many m3 of gold are in the oceans? (c) Assuming the price of gold is $370.00/troy oz. What is the value of gold in the oceans (1 troy oz = 31.1 g; d of gold = \(19.3\ \text{g/cm}^3\))?

                                                   

Step-by-Step Solution:

Step 1 of 3

(a)

From the given,

Surface area =

Let’s convert the surface area “km” into “m”.

Depth = 3800m

Concentration = .

Let’s calculate the number of grams of gold in the ocean.


                                                           

                                                           

                                                           

Therefore, the number of grams of gold in the ocean is

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Step 2 of 3

Chapter 1, Problem 71P is Solved
Step 3 of 3

Textbook: Principles of General Chemistry
Edition: 2
Author: Martin S. Silberberg
ISBN: 9780073511085

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