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# Earth’s oceans have an average depth of 3800 m, a total area of 3.63x10^8 km^2 , and an average concentration of dissolved gold of 5.8x10^-9 g/L. How many grams of gold are in the oceans?

ISBN: 9780073511085 71

## Solution for problem 71P Chapter 1

Principles of General Chemistry | 2nd Edition

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Problem 71P

Earth’s oceans have an average depth of 3800 m, a total area of $$3.63\times10^8\ \text{km}^2$$, and an average concentration of dissolved gold of $$5.8\times10^{-9}\ \text{g/L}$$. (a) How many grams of gold are in the oceans? (b) How many m3 of gold are in the oceans? (c) Assuming the price of gold is \$370.00/troy oz. What is the value of gold in the oceans (1 troy oz = 31.1 g; d of gold = $$19.3\ \text{g/cm}^3$$)?

Step-by-Step Solution:

Step 1 of 3

(a)

From the given,

Surface area =

Let’s convert the surface area “km” into “m”.

Depth = 3800m

Concentration = .

Let’s calculate the number of grams of gold in the ocean.

Therefore, the number of grams of gold in the ocean is

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Step 2 of 3

Step 3 of 3

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