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# Solved: Calculate each of the following quantities:(a)

## Problem 12P Chapter 3

Principles of General Chemistry | 2nd Edition

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Principles of General Chemistry | 2nd Edition

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Problem 12P Problem 12P

Calculate each of the following quantities:

(a) Mass in kilograms of 4.6×1021 molecules of NO2

(b) Moles of Cl atoms in 0.0615 g of C2H4C12

(c) Number of H− ions in 5.82 g of SrH2

Step-by-Step Solution:

Solution 12P:

Here, we are going to calculate the following quantities.

Step 1:

(a) Mass in kilograms of 4.6×1021 molecules of NO2

Here, we have to calculate the mass in kg of 4.6×1021 molecules of NO2

We know that,

The molar mass of NO2 =  46.01g/mol

Given that,

Number of the solute = 4.6×1021 molecules

Therefore,

1.0 mole of NO2 = 6.022 x1023 molecules of NO2

Thus,

The mole of NO2 =4.6×1021 molecules  = 7.638 10-3 moles of NO2

We know that,

1.0 mole of NO2 = 46.01 g

Therefore,

The mass of NO2 = 7.638 10-3 moles of NO2 = 351.4210-3 g

We know,

1000 g =1.0 kg

Therefore, the mass of NO2 in kg = 351.4210-3 g = 3.5110-4 kg

Step 2:

(b) Moles of Cl atoms in 0.0615 g of C2H4C12

Here, we have to calculate the moles of Cl atoms in 0.0615 g of C2H4C12

We know that,

The molar mass of  C2H4C12 =98.95 g/mol

Given that,

Mass of the solute = 0.0615 g

Thus,

98.95 g of C2H4C12 = 1.0 mole

Therefore,

The moles of C2H4C12 =0.0615 g =  6.215 x 10–4 moles of C2H4C12

The dissociation of C2H4C12 gives:

C2H4C122C + 4H + 2 Cl

Therefore,

1.0 mole of C2H4C12= 2.0 moles of Cl atoms

Thus,

The moles of Cl atoms = 6.215 x 10–4 moles of C2H4C12

= 6.215 x 10–4 moles of Cl atoms

Therefore, 6.215 x 10–4 moles of Cl atoms is in 0.0615 g of C2H4C12.

Step 3 of 3

##### ISBN: 9780073511085

The answer to “Calculate each of the following quantities:(a) Mass in kilograms of 4.6×1021 molecules of NO2(b) Moles of Cl atoms in 0.0615 g of C2H4C12(c) Number of H? ions in 5.82 g of SrH2” is broken down into a number of easy to follow steps, and 32 words. This textbook survival guide was created for the textbook: Principles of General Chemistry, edition: 2nd. Principles of General Chemistry was written by Sieva Kozinsky and is associated to the ISBN: 9780073511085. Since the solution to 12P from 3 chapter was answered, more than 299 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 12P from chapter: 3 was answered by Sieva Kozinsky, our top Chemistry solution expert on 08/31/17, 03:54AM. This full solution covers the following key subjects: atoms, calculate, ions, kilograms, mass. This expansive textbook survival guide covers 23 chapters, and 1878 solutions.

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