Solution Found!
Many metals react with oxygen gas to form the metal oxide.
Chapter 3, Problem 48P(choose chapter or problem)
Many metals react with oxygen gas to form the metal oxide. For example, calcium reacts as follows:
\(2 \mathrm{Ca}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{CaO}(\mathrm{s})\)
You wish to calculate the mass of calcium oxide that can be prepared from \(4.20 g\) of Ca and \(2.80 g\) of \(\mathrm{O}_{2}\).
(a) How many moles of CaO can form from the given mass of Ca?
(b) How many moles of CaO can form from the given mass of \(\mathrm{O}_{2}\)?
(c) Which is the limiting reactant?
(d) How many grams of CaO can form?
Questions & Answers
QUESTION:
Many metals react with oxygen gas to form the metal oxide. For example, calcium reacts as follows:
\(2 \mathrm{Ca}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{CaO}(\mathrm{s})\)
You wish to calculate the mass of calcium oxide that can be prepared from \(4.20 g\) of Ca and \(2.80 g\) of \(\mathrm{O}_{2}\).
(a) How many moles of CaO can form from the given mass of Ca?
(b) How many moles of CaO can form from the given mass of \(\mathrm{O}_{2}\)?
(c) Which is the limiting reactant?
(d) How many grams of CaO can form?
ANSWER:
Step 1 of 5
The given chemical reaction is,
\(2 \mathrm{Ca}+\mathrm{O}_{2} \rightarrow 2 \mathrm{CaO}\)
(a) Here we have to calculate how many moles of CaO can be produced from the given mass of Ca.
In the above balanced reaction 2 moles of CaO has formed from 2 moles of Ca.
The given mass of Ca = 4.20 g
Mass of \(\mathrm{O}_{2}\) = 2.80 g