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Aluminum nitrite and ammonium chloride react to form
Chapter 3, Problem 54P(choose chapter or problem)
Aluminum nitrite and ammonium chloride react to form aluminum chloride, nitrogen, and water. What mass of each substance is present after 72.5 g of aluminum nitrite and 58.6 g of ammonium chloride react completely?
Questions & Answers
QUESTION:
Aluminum nitrite and ammonium chloride react to form aluminum chloride, nitrogen, and water. What mass of each substance is present after 72.5 g of aluminum nitrite and 58.6 g of ammonium chloride react completely?
ANSWER:Step 1 of 3
Here, we are going to calculate the mass of each substance is present after the reaction.
The balanced chemical equation is:
Determination of limiting reagent:
Calculation of the moles of from the moles of if we consider as a limiting agent:
Given that,
The mass of = 72.5 g
The molar mass of = 165.01 g/mol
Therefore,
The moles of is
= (72.5 g ) = 0.439367 mol
Thus,
The moles of from the moles of
= (0.439367 mol ) = 0.439367 mol
0.439367 mol is formed from 0.439367 mol .