Aluminum nitrite and ammonium chloride react to form

Chapter 3, Problem 54P

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QUESTION:

Aluminum nitrite and ammonium chloride react to form aluminum chloride, nitrogen, and water. What mass of each substance is present after 72.5 g of aluminum nitrite and 58.6 g of ammonium chloride react completely?

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QUESTION:

Aluminum nitrite and ammonium chloride react to form aluminum chloride, nitrogen, and water. What mass of each substance is present after 72.5 g of aluminum nitrite and 58.6 g of ammonium chloride react completely?

ANSWER:

Step 1 of 3

Here, we are going to calculate the mass of each substance is present after the reaction.

The balanced chemical equation is:

       

Determination of limiting reagent:

Calculation of the moles of  from the moles of   if we consider  as a limiting agent:

Given that,

The mass of  = 72.5 g

The molar mass of  = 165.01 g/mol

Therefore,

The moles of  is

           = (72.5 g )    = 0.439367 mol  

Thus,

The moles of  from the moles of  

           = (0.439367 mol )  = 0.439367 mol

0.439367 mol  is formed from 0.439367 mol .

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