Calcium nitrate and ammonium fluoride react to form

Step 1 of 3

Here, we are going to calculate the mass of each substance is present after the reaction.

The balanced chemical equation is:

Determination of limiting reagent:

Calculation of the moles of  from the moles of  if we consider  as a limiting agent:

Given that,

The mass of  =16.8 g

The molar mass of  =164.10 g/mol

Therefore,

The moles of  is

= (16.8 g )   = 0.1023766 mol

Thus,

The moles of from the moles of

= 0.1023766 mol  

= 0.1023766 mol = 0.102 mol

Therefore, 0.102 mol  is formed from 0.1023766 mol