When 0.100 mol of carbon is burned in a closed vessel with

Chapter 3, Problem 52P

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QUESTION: Problem 52P

When 0.100 mol of carbon is burned in a closed vessel with 8.00 g of oxygen, how many grams of carbon dioxide can form? Which reactant is in excess, and how many grams of it remain after the reaction?

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QUESTION: Problem 52P

When 0.100 mol of carbon is burned in a closed vessel with 8.00 g of oxygen, how many grams of carbon dioxide can form? Which reactant is in excess, and how many grams of it remain after the reaction?

ANSWER:

Solution 52P:

The solution is based on limiting reagent.

Step 1:

The balanced equation is

Here, we are calculating the moles of  from the moles of carbon if we consider O2 is limiting reagent:

We know that,

Moles of from C = (0.100 mol C)= 0.100 mol of CO2(g)

Thus, 0.100 mol of CO2(g) is formed from the moles of carbon if we consider O2 is limiting reagent.

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