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When 20.5 g of methane and 45.0 g of chlorine gas undergo
Chapter 3, Problem 60P(choose chapter or problem)
QUESTION: When 20.5 g of methane and 45.0 g of chlorine gas undergo a reaction that has a 75.0% yield, what mass of chloromethane (\(CH_3Cl\)) forms? Hydrogen chloride also forms.
Questions & Answers
QUESTION: When 20.5 g of methane and 45.0 g of chlorine gas undergo a reaction that has a 75.0% yield, what mass of chloromethane (\(CH_3Cl\)) forms? Hydrogen chloride also forms.
ANSWER:
Solution 60P:
Here, we are going to determine the mass of chloromethane and hydrogen chloride formed.
Step 1:
The percent yield is calculated as follows:
----(1)
The actual yield is defined as the amount of product actually produced by a chemical reaction.
The theoretical yield is defined as the amount of product that can be made in a chemical
reaction based on the amount of limiting reactant.