When 20.5 g of methane and 45.0 g of chlorine gas undergo

Chapter 3, Problem 60P

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QUESTION: When 20.5 g of methane and 45.0 g of chlorine gas undergo a reaction that has a 75.0% yield, what mass of chloromethane (\(CH_3Cl\)) forms? Hydrogen chloride also forms.

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QUESTION: When 20.5 g of methane and 45.0 g of chlorine gas undergo a reaction that has a 75.0% yield, what mass of chloromethane (\(CH_3Cl\)) forms? Hydrogen chloride also forms.

ANSWER:

Solution 60P:

Here, we are going to determine the mass of chloromethane and hydrogen chloride formed.

Step 1:

The percent yield is calculated as follows:

----(1)

The actual yield is defined as  the amount of product actually produced by a chemical reaction.

The theoretical yield is defined as the amount of product that can be made in a chemical

reaction based on the amount of limiting reactant.

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