A 27.7-g sample of ethylene glycol, a car radiator

Chapter 5, Problem 25P

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QUESTION: Problem 25P

A 27.7-g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/g·K)?

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QUESTION: Problem 25P

A 27.7-g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/g·K)?

ANSWER:

Solution 25P:

Here, we are going to calculate the final temperature of ethylene glycol.

Step 1:

We know that,

The heat capacity is directly related with the temperature change.

Where c is the heat capacity, q is the heat absorbed by the object

m is the mass of the object

 is the change in temperature =(

Therefore,

(=----(1)

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