Solution Found!
A 27.7-g sample of ethylene glycol, a car radiator
Chapter 5, Problem 25P(choose chapter or problem)
A 27.7-g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/g·K)?
Questions & Answers
QUESTION: Problem 25P
A 27.7-g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/g·K)?
ANSWER:
Solution 25P:
Here, we are going to calculate the final temperature of ethylene glycol.
Step 1:
We know that,
The heat capacity is directly related with the temperature change.
Where c is the heat capacity, q is the heat absorbed by the object
m is the mass of the object
is the change in temperature =(
Therefore,
(=----(1)