Solution Found!
Write the balanced overall equation (equation 3) for the
Chapter 5, Problem 46P(choose chapter or problem)
Write the balanced overall equation for the following process (equation 3), calculate \(\Delta H_{\text {overall }}\), and match the number of each equation with the letter of the appropriate arrow in Figure P6.46:
(1) \(\mathrm{N}_2(g)+\mathrm{O}_2(g)\ \longrightarrow\ 2\mathrm{NO}(g)\) \(Delta H=180.6\mathrm{\ kJ}\)
(2) \(2\mathrm{NO}(g)+\mathrm{O}_2(g)\ \longrightarrow\ 2\mathrm{NO}_2(g)\) \(\Delta H=-114.2\mathrm{\ kJ}\)
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(3) \(\Delta H_{\text{overall }}\ =\ ?\)
Equation Transcription:
Text Transcription:
Delta H_overall
N_2 (g) + O_2 (g) rightarrow 2NO(g)
Delta H = 180.6 kJ
2NO(g) + O_(g) rightarrow 2NO_2 (g)
Delta H = -114.2 kJ
Delta H_overall
Questions & Answers
QUESTION:
Write the balanced overall equation for the following process (equation 3), calculate \(\Delta H_{\text {overall }}\), and match the number of each equation with the letter of the appropriate arrow in Figure P6.46:
(1) \(\mathrm{N}_2(g)+\mathrm{O}_2(g)\ \longrightarrow\ 2\mathrm{NO}(g)\) \(Delta H=180.6\mathrm{\ kJ}\)
(2) \(2\mathrm{NO}(g)+\mathrm{O}_2(g)\ \longrightarrow\ 2\mathrm{NO}_2(g)\) \(\Delta H=-114.2\mathrm{\ kJ}\)
____________________________________________________________________________
(3) \(\Delta H_{\text{overall }}\ =\ ?\)
Equation Transcription:
Text Transcription:
Delta H_overall
N_2 (g) + O_2 (g) rightarrow 2NO(g)
Delta H = 180.6 kJ
2NO(g) + O_(g) rightarrow 2NO_2 (g)
Delta H = -114.2 kJ
Delta H_overall
ANSWER:
Solution 46P
Here we have to write the balanced overall equation (equation 3) for the following process, calculate Δ H overall, and match the number of each equation with the letter of the appropriate arrow in Figure P6.67: