Solved: In Exercises 57 and 58, find the points at which the graph of the equation has a

Chapter 2, Problem 57

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In Exercises 57 and 58, find the points at which the graph of the equation has a vertical or horizontal tangent line.

\(25x^2+16y^2+200x-160y+400=0\)

Text Transcription:

25x^2 +16y^2 +200x -160y +400 =0

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