The emergent velocity of a liquid flowing from a hole in the bottom of a tank is given

Chapter 2, Problem 102

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Fluid Flow   The emergent velocity v of a liquid flowing from a hole in the bottom of a tank is given by \(v=\sqrt{2 g h}\), where g is the acceleration due to gravity (32 feet per second per second) and h is the depth of the liquid in the tank. Find the rates of change of v with respect to h when (a) h = 9 and (b) h = 4. (Note that g = +32 feet per second per second. The sign of g depends on how a problem is modeled. In this case, letting g be negative would produce an imaginary value for v.)

Text Transcription:

v=sqrt 2gh

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