Answer: Suppose the function is defined on as shown in the figure. Show that does not
Chapter 4, Problem 76(choose chapter or problem)
Suppose the function is defined on as shown in the figure.
\(f(x)=\left\{\begin{array}{ll}0, & x=0 \\\frac{1}{x}, & 0<x \leq 1\end{array}\right.\)
Show that \(\int_{0}^{1} f(x) d x\) does not exist. Why doesn’t this contradict Theorem 4.4?
Text Transcription:
f(x)= {^0, x=0 _1/x, 0<x leq 1
\int_{0}^{1} f(x) d x
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