Solved: In Exercises 61 68, find an equation of the tangent line to the graph of the
Chapter 5, Problem 64(choose chapter or problem)
In Exercises 61-68, find an equation of the tangent line to the graph of the function at the given point.
\(y=\ln\frac{e^x+e^{-x}}{2},\quad\ \ (0,\ 0)\)
Text Transcription:
y = ln e^x + e^-x / 2, (0, 0)
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