Solution Found!
Answer: How would you prepare the following aqueous
Chapter 14, Problem 52P(choose chapter or problem)
Problem 52P
How would you prepare the following aqueous solutions?
(a) 1.50 kg of 0.0355 m ethanol (C2H5OH) from ethanol and water
(b) 445 g of 13.0 mass % HCI from 34.1 mass % HCl
Questions & Answers
QUESTION:
Problem 52P
How would you prepare the following aqueous solutions?
(a) 1.50 kg of 0.0355 m ethanol (C2H5OH) from ethanol and water
(b) 445 g of 13.0 mass % HCI from 34.1 mass % HCl
ANSWER:
Solution 52P
Step 1: (a)
Here, we are going to prepare the following aqueous solution.
Total mass of the solution = mass of solute + mass of solvent.
Mass of solution = = 0.00163 g
Calculate total mass of the solution in grams as follows:
Thus,
Total mass of the solution = (1000 +0.00163 ) g =1000.0016 g
Calculate mass of ethanol as follows:
1.50 × 103 g = 2.45 g
Therefore, the mass of the solvent = (1500 -0.00245) g =1499.99 g
Therefore, 2.45 g of solvent is added to 1499.99 g of water.