The rate law for the general reaction is rate = k[A] m[B]

Chapter 16, Problem 20P

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QUESTION:

The rate law for the general reaction

\(a \mathrm{~A}+b \mathrm{~B}+\cdots \longrightarrow c \mathrm{C}+d \mathrm{D}+\cdots\)

is rate = \(k[\mathrm{~A}]^{m}[\mathrm{~B}]^{n} \cdots\)

(a) Explain the meaning of ๐‘˜.

(b) Explain the meanings of ๐‘š and ๐‘›. Does ๐‘š = ๐‘Ž and ๐‘› = ๐‘? Explain.

(c) If the reaction is first order in A and second order in B, and time is measured in minutes (min), what are the units for ๐‘˜?

Equation Transcription:

Text Transcription:

aA+bB+... rightarrow cC+dD+...

k[A]^m[B]^n...

Questions & Answers

QUESTION:

The rate law for the general reaction

\(a \mathrm{~A}+b \mathrm{~B}+\cdots \longrightarrow c \mathrm{C}+d \mathrm{D}+\cdots\)

is rate = \(k[\mathrm{~A}]^{m}[\mathrm{~B}]^{n} \cdots\)

(a) Explain the meaning of ๐‘˜.

(b) Explain the meanings of ๐‘š and ๐‘›. Does ๐‘š = ๐‘Ž and ๐‘› = ๐‘? Explain.

(c) If the reaction is first order in A and second order in B, and time is measured in minutes (min), what are the units for ๐‘˜?

Equation Transcription:

Text Transcription:

aA+bB+... rightarrow cC+dD+...

k[A]^m[B]^n...

ANSWER:

Solution 20P

Step 1

(a) Here we have to explain the meaning of k.

The rate law for the general reaction

is rate = k[A] m[B] nยทยทยท

k is the rate constant or proportionality constant in the rate law and is depends on temperature i.e k varies with temperature. k represents the fraction of successful collisions which includes the fraction of collisions with sufficient energy and fraction of collisions with correct orientation.

Thus k is the rate constant.

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