Sodium bicarbonate undergoes thermal decomposition

Chapter 17, Problem 54P

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QUESTION:

Sodium bicarbonate undergoes thermal decomposition according to the reaction

\(2\mathrm{NaHCO}_3(\mathrm{s})\ \rightleftharpoons\mathrm{\ Na}_2\mathrm{CO}_3(s)+\mathrm{CO}_2(\mathrm{g})+\mathrm{H}_2\mathrm{O}(\mathrm{g})\)

How does the equilibrium position shift when?

(a) 0.20 atm of argon gas is added.

(b) \(\mathrm{NaHCO}_{3}(s)\) is added,

(c) \(\mathrm{Mg}\left(\mathrm{ClO}_{4}\right)_{2}(s)\) is added as a drying agent to remove \(\mathrm{H}_{2} \mathrm{O}\).

(d) Dry ice is added at constant temperature.

Questions & Answers

QUESTION:

Sodium bicarbonate undergoes thermal decomposition according to the reaction

\(2\mathrm{NaHCO}_3(\mathrm{s})\ \rightleftharpoons\mathrm{\ Na}_2\mathrm{CO}_3(s)+\mathrm{CO}_2(\mathrm{g})+\mathrm{H}_2\mathrm{O}(\mathrm{g})\)

How does the equilibrium position shift when?

(a) 0.20 atm of argon gas is added.

(b) \(\mathrm{NaHCO}_{3}(s)\) is added,

(c) \(\mathrm{Mg}\left(\mathrm{ClO}_{4}\right)_{2}(s)\) is added as a drying agent to remove \(\mathrm{H}_{2} \mathrm{O}\).

(d) Dry ice is added at constant temperature.

ANSWER:

 

Step 1 of 5

Here, we are going to find the influence of the following factors that affect the equilibrium position shift as a result of disturbances.

 

(a)  0.20 atm of argon gas is added

Given that the equilibrium system:

\(2 \mathrm{NaHCO}_{3}(s) \rightleftharpoons \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\)

 

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