Answer: In Exercises 14, verify the formula
Chapter 9, Problem 4(choose chapter or problem)
In Exercises 1-4, verify the formula.
\(\frac{1}{1\cdot3\cdot5\cdot\cdot(2k-5)}=\frac{2^kk!(2k-3)(2k-1)}{(2k)!},\quad\ \ k\ \ge\ 3\)
Text Transcription:
1 / 1 cdot 3 cdot 5 cdots (2k-5) = 2^k k! (2k-3)(2k-1) / (2k)!, k geq 3
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer