Solution: In Exercises 73 and 74, write an equivalent series with the index of summation
Chapter 9, Problem 74(choose chapter or problem)
In Exercises 73 and 74, write an equivalent series with the index of summation beginning at n = 0.
\(\sum_{n=2}^{\infty} \frac{9^{n}}{(n-2) !}\)
Text Transcription:
sum_n=2 ^infty 9^n / (n-2)!
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