Solution Found!
Calculate the pH during the titration of 40.00 mL of
Chapter 20, Problem 39P(choose chapter or problem)
Calculate the pH during the titration of 40.00 mL of 0.1000 M HCl with 0.1000 M NaOH solution after the following additions of base:
(a) 0 mL
(b) 25.00 mL
(c) 39.00 ml.
(d) 39.90 mL
(e) 40.00 mL
(f) 40.10 mL
(g) 50.00 mL
Questions & Answers
QUESTION:
Calculate the pH during the titration of 40.00 mL of 0.1000 M HCl with 0.1000 M NaOH solution after the following additions of base:
(a) 0 mL
(b) 25.00 mL
(c) 39.00 ml.
(d) 39.90 mL
(e) 40.00 mL
(f) 40.10 mL
(g) 50.00 mL
ANSWER:Step 1 of 8
The Neutralization process involves the reaction between an acid and a base to give a corresponding salt and water.
The number of moles of hydrogen and hydroxide ions (Arrhenius base) is equal for complete neutralization.
This number depends on the basicity of the acid and the acidity of the base.
The product of the molar concentration and the volume gives us the number of moles.
The reaction between hydrochloric acid and sodium hydroxide takes place as:
Since both the reactants are strong electrolytes, they dissociate completely into their ions and the concentration of HCl is considered for the calculation of pH.