Solution Found!
Find the pH during the titration of 20.00 mL of 0.1000 M
Chapter 20, Problem 41P(choose chapter or problem)
Find the pH during the titration of 20.00 mL of 0.1000 M butanoic acid, , With 0.1000 M NaOH solution after the following additions of titrant:
(a) 0 mL
(b) 10.00mL
(c) 15.00mL
(d) 19.00mL
(e) 19.95 mL
(f) 20.00 mL
(g) 20.05 mL
(h) 25.00 mL
Questions & Answers
QUESTION:
Find the pH during the titration of 20.00 mL of 0.1000 M butanoic acid, , With 0.1000 M NaOH solution after the following additions of titrant:
(a) 0 mL
(b) 10.00mL
(c) 15.00mL
(d) 19.00mL
(e) 19.95 mL
(f) 20.00 mL
(g) 20.05 mL
(h) 25.00 mL
ANSWER:
Step 1 of 8
pH is a parameter that describes the “strength of acid/base” present in the solution. The formula to evaluate pH is given below:
Where
*
Given data:
Volume of butanoic acid is 20.00 mL or 0.02 L.
Concentration of butanoic acid is 0.100 M.
Dissociation constant of acid is 
Concentration of NaOH is 0.1000 M.
(a) When volume is 0 mL
The reaction of butanoic acid and water is given below:
Its equilibrium equation is:
The dissociation constant of the base is calculated as:
The concentration of 
Thus, from the concentration of hydronium ions, pH can be evaluated:
So, the pH of the solution is 2.90.