Solution: In Exercises 14, state where the power series is centered
Chapter 9, Problem 2(choose chapter or problem)
In Exercises 1–4, state where the power series is centered.
\(\sum_{n=1}^{\infty} \frac{(-1)^{n} 1 \cdot 3 \cdot(2 n-1)}{2^{n} n !} x^{n}\)
Text Transcription:
sum_n = 1 ^infty (-1)^n 1 cdot 3 cdots (2n - 1) / 2^n n! x^n
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