In basic solution, Se2? and SO32? ions react
Chapter 22, Problem 27P(choose chapter or problem)
In basic solution, \(\mathrm{Se}^{2-}\) and \(\mathrm{SO}_{3}{ }^{2-}\) ions react spontaneously:
\(\begin{aligned}&2 \mathrm{Se}^{2-}(a q)+2 \mathrm{SO}_{3}{ }^{2-}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \\&2 \mathrm{Se}(s)+6 \mathrm{OH}^{-}(a q)+\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2-}(a q)\end{aligned} \quad E_{\text {cell }}^{\circ}=0.35 \mathrm{~V}\)
(a) Write balanced half-reactions for the process.
(b) If \(E_{\text {sulfite }}^{\circ}\) is \(-0.57 \mathrm{~V}\), calculate \(E_{\text {selenium }}^{\circ}\).
Equation Transcription:
Text Transcription:
Se^2-
SO_3^2-
2Se^2-(aq)+2SO_3^2-(aq)+3H_2O(l) longrightarrow Se(s)+6OH^-(aq)+S_2 O_3^2-(aq) E_cell^circ =0.35 V E_sulfite^circ
−0.57 V
E_selenium^circ
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