Get solution: In Exercises 916, the initial and terminal points of a vector are given

Chapter 10, Problem 11

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In Exercises 5-14, find dy/dx and \(d^2y/dx^2\), and find the slope and concavity (if possible) at the given value of the parameter.

Parametric Equations                                                       Point

\(x=2+ \sec \theta,\ \ y=1+2 \tan \theta\)                            \(\theta=\frac{\pi}{6}\)

Text Transcription:

d^2 y / dx^2

x=2 + sec theta, y=1+2 tan theta

theta=pi/6

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