Solve for in the triple integral
Chapter 14, Problem 75(choose chapter or problem)
Solve for a in the triple integral.
\(\int_{0}^{1} \int_{0}^{3-a-y^{2}} \int_{a}^{4-x-y^{2}} d z d x d y=\frac{14}{15}\)
Text Transcription:
int_0 ^1 int_0 ^3 - a - y^2 int_a ^4 - x - y^2 dz dx dy = 14/15
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