Integrating eax sin bx by parts twice gives,eax sin bx dx = eax(A sin bx + B cos bx) +

Chapter 7, Problem 65

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Integrating eax sin bx by parts twice gives,eax sin bx dx = eax(A sin bx + B cos bx) + C.(a) Find the constants A and B in terms of a and b.[Hint: Dont actually perform the integration.](b) Evaluate - eax cos bx dx by modifying the methodin part (a). [Again, do not perform the integration.]

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