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Write the symbol for each element and classify it as a

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 64E Chapter 2

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 64E

Write the symbol for each element and classify it as a metal, nonmetal, or metalloid.

a.        gold

b.        fluorine

c.        sodium

d.        tin

e.        argon

Step-by-Step Solution:

Solution : Step 1 : Here, The table with ions of the elements are given. we have to fill the blank spaces in table by the ionic compound formed from the ions. Step 2 : Now let’s consider each set of data in the table and write the chemical formulas for the compounds formed from the ions : Step 3: Let’s consider the 1st set of data (ions formed with O ): 2- (i) The Ions are O and Na . O is the chemical symbol of Oxygen. Na is the chemical symbol of S odium. Given, the charge of O is -2 and Na has charge of +1. This indicates that 1 O ion is 2- + required to neutralize 2 Na ions. Hence the chemical formula of the compound formed is Na O. 2 (ii) The Ions are O and Ca . O is the chemical symbol of Oxygen. Ca is the chemical symbol of Calcium. Given, the charge of O is -2 and Ca has charge of 2+. This indicates that 1 O ion is 2- required to neutralize 1 Ca ion. Hence the chemical formula of the compound formed is CaO. (iii) The Ions are O and Fe . O is the chemical symbol of Oxygen. Fe is the chemical symbol of Iron. Given, the charge of O is -2 and Fe has charge of 2+. This indicates that 1 O ion is 2- required to neutralize 1 Fe ion. Hence the chemical formula of the compound formed is FeO. (iv) The Ions are O and Al . O is the chemical symbol of Oxygen. Al is the chemical symbol of Aluminium. Given, the charge of O is -2 and Al has charge of 3+. This indicates that 3 O ions are 2- 3+ required to neutralize 2 Al ions. Hence the chemical formula of the compound formed is Al 2 .3 Step 4 : - Let’s consider the 1st set of data (ions formed with NO ): 3 (i) The Ions are NO and Na . NO is the chemical symbol of Nitrate. Na is the chemical 3 3 symbol of S odium. Given, the charge of NO is -1 and Na has3harge of +1. This indicates that 1 NO ion is 3- + required to neutralize 1 Na ion. Hence the chemical formula of the compound formed is NaNO . 3 (ii) The Ions are NO and Ca . NO3s the chemical symbol of 3itrate. Ca is the chemical symbol of Calcium. - Given, the charge of NO is -1 and Ca has3harge of 2+. This indicates that 2 NO ions 3 2+ are required to neutralize 1 Ca ion. Hence the chemical formula of the compound formed is Ca(NO ) . 3 2 (iii) - 2+ The Ions are NO and Fe . NO3s the chemical symbol of 3itrate. Fe is the chemical symbol of Iron. Given, the charge of NO is -1 and Fe has charge of 2+. This indicates that 2 NO ions - 3 3 are required to neutralize 1 Fe ion. Hence the chemical formula of the compound formed is Fe(NO ) . 3 2 (iv) - 3+ The Ions are NO and Al . NO3s the chemical symbol o3Nitrate. Al is the chemical symbol of Aluminium. Given, the charge of NO is -1 and Al has3harge of 3+. This indicates that 3 NO ions 3 3+ are required to neutralize 1 Al ion. Hence the chemical formula of the compound formed is Al(NO ) . 3 3

Step 5 of 7

Chapter 2, Problem 64E is Solved
Step 6 of 7

Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

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