Fill in the blanks in the following table: Cation Anion

Solution : Step 1: Let’s consider 1st set of data, i.e row 1 : Here we are given the name of the compound from which we have to predict the cation, anion and the molecular formula. The name of the compound is Lithium oxide. This compound is made of Lithium ion + 2- (Li ), which is a cation as it is metal and oxide ion(O ), which is a anion. Since the charges of the ions are not equal, the charge of one ion becomes the subscript of another. Hence, we write the molecular formula for L ithium oxide is Li O2 Step 2: Now let’s consider 2nd row : Here, the cation and anion is given. We have to find the molecular formula and name of the compound. The given cation is Fe 2+ and anion is PO . F4- 2+ is the Iron(II) ion and PO 4-is the Phosphate ion. The roman numeral II is because iron is a transition metal and hence it has multiple oxidation states and thus the charge will be indicated through roman numeral. So we have the chemical name of the compound as Iron(II) phosphate and since the charges of the ions are not equal, the charge of one ion becomes the subscript of another. Hence, we write the molecular formula as F e3PO 4 2. Step 3: Now let’s consider 3rd row : In the 3rd row, we are given with the molecular formula, we need to identify the cation and anion along with the name of the compound. Molecular formula given is Al (SO ) .2rom 4 3olecular formula we can predict that the charge of one has become subscript of other ion, and It is made up of Aluminium(Al) and its charge will be 3+ and is a cation and Sulfate ion(SO ) which is a an4n and the name of the compound as Aluminium Sulphate. Step 4: Now let’s consider 4th row : Name of the compound is given as Copper(II) nitrate. The roman numeral II, indicates that the copper(Cu), a metal has charge of 2+ and is a cation and nitrate ion(NO ) is anion. The - 3 charges of ions are unequal and hence the charge of one ion becomes the subscript of other. Hence, the molecular formula for the compound will be C u(NO )3 2 Step 5 : Now let’s consider 5th row : Here, the cation and anion is given. We have to find the molecular formula and name of the compound. The given cation is Cr 3+ and anion is I. Cr 3+ is the Chromium(III) ion and I is the - Iodide ion. The roman numeral III is because chromium is a transition metal and hence it has multiple oxidation states and thus the charge will be indicated through roman numeral. So we have the chemical name of the compound as Chromium(III) iodide and since the charges of the ions are not equal, the charge of one ion becomes the subscript of another. Hence, we write the molecular formula as CrI 3.