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# Iron in the earth is in the form of iron ore. Common ores ISBN: 9780321809247 1

## Solution for problem 74E Chapter 3

Chemistry: A Molecular Approach | 3rd Edition

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Problem 74E

Iron in the earth is in the form of iron ore. Common ores include (hematite), (magnetite), and FeC03 (siderite). Calculate the mass percent composition of iron for each of these iron ores. Which ore has the highest iron content?

Step-by-Step Solution:

Solution 74E Step-by-step solution Step 1 of 5 Given in the question A bottling plant has 126,515 bottles with a capacity of 355ml,108,500 caps and 48,755 l of beverage In a bottling plant Number of bottles =126,515 Volume of each bottle=355ml =355ml*1 L/10 ml =0.355L. Number of caps=108,500 caps. Volume of beverage=48,775l. Step 2 of 5 Step 3 of 5 In the bottling plant we have 126,515 bottles and 108,500 caps .so here the caps are the limiting value are the limiting value and thus no caps will be left. One bottle needs one cap so the number of bottles left is total number of bottles minus number of caps The bottles left=(126,515-108,500) =18,015

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##### ISBN: 9780321809247

The full step-by-step solution to problem: 74E from chapter: 3 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. Since the solution to 74E from 3 chapter was answered, more than 282 students have viewed the full step-by-step answer. The answer to “Iron in the earth is in the form of iron ore. Common ores include (hematite), (magnetite), and FeC03 (siderite). Calculate the mass percent composition of iron for each of these iron ores. Which ore has the highest iron content?” is broken down into a number of easy to follow steps, and 39 words. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. This full solution covers the following key subjects: bottles, left, bottling, capacity, capped. This expansive textbook survival guide covers 82 chapters, and 9464 solutions.

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