Solved: Limiting Reactants (Section)Sodium hydroxide
Chapter , Problem 77E(choose chapter or problem)
Limiting Reactants (Section 3.7)
Sodium hydroxide reacts with carbon dioxide as follows:
\(2\ \mathrm{NaOH}(s)+\mathrm {CO}_{2}(g) \longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}({l})\)
Which is the limiting reactant when 1.85 mol \(\mathrm{NaOH}\) and 1.00 mol \(\mathrm{CO}_{2}\) are allowed to react? How many moles of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) can be produced? How many moles of the excess reactant remain after the completion of the reaction?
Equation Transcription:
Text Transcription:
2 NaOH(s)+CO_{2}(g){rightarrow}Na_{2}CO_{3}(s)+H_{2}O(l)
NaOH
CO_2
Na_{2}CO_3
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