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Limiting Reactants (Section) Aluminum hydroxide reacts

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 78 Chapter 3

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 78

Limiting Reactants (Section) Aluminum hydroxide reacts with sulfuric acid as follows: Which is the limiting reactant when 0.500 mol AI(OH)3 and 0.500 mol H2SO4 are allowed to react? How many moles of AI2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?

Step-by-Step Solution:

Solution 78 Step 1 of 3 Step 2 of 3 Moles of Al2(SO4)3 formed Moles of Al2(SO4)3= 1 mol Al2(SO4)3/3 mol H2SO4*0.500mol H2SO4 =0.1667 mol Al2(SO4)3. =0.167mol.

Step 3 of 3

Chapter 3, Problem 78 is Solved
Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

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Limiting Reactants (Section) Aluminum hydroxide reacts

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