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Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 5.9 - Problem 7
Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 5.9 - Problem 7

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# ?In Exercises 7-14, verify the identity. $$\tanh ^{2} x+\operatorname{sech}^{2} x=1$$ ISBN: 9781285774770 141

## Solution for problem 7 Chapter 5.9

Calculus: Early Transcendental Functions | 6th Edition

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Problem 7

In Exercises 7-14, verify the identity.

$$\tanh ^{2} x+\operatorname{sech}^{2} x=1$$

Text Transcription:

\tanh ^2 x+sech^2 x=1

Step-by-Step Solution:

Step 1 of 5) The graphs of the functions ƒ(x) = x-1 = 1>x and g(x) = x-2 = 1>x2 are shown in Figure 1.16.

Step 2 of 2

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?In Exercises 7-14, verify the identity. $$\tanh ^{2} x+\operatorname{sech}^{2} x=1$$